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Line BE and lineCF are angle bisectors of triangle ABC that meet at I as shown below, and we have CE = 4, AE = 6, and AB = 8. Find BC.
Thanks so much!
EDIT: Solved this one! It's 16/3 :)
The angle bisector of B sets up the following ratio :
BC / AB = CE / AE
BC / 8 = 4 / 6 multiply both sides by 8
BC = 8 * 4 / 6 = 32 / 6 = 16 / 3