Line BE and lineCF are angle bisectors of triangle ABC that meet at I as shown below, and we have CE = 4, AE = 6, and AB = 8. Find BC.

Thanks so much!

EDIT: Solved this one! It's 16/3 :)

The angle bisector of B sets up the following ratio :

BC / AB = CE / AE

BC / 8 = 4 / 6 multiply both sides by 8

BC = 8 * 4 / 6 = 32 / 6 = 16 / 3

Thanks CPhill!