Find the equation of the line that passes through (-1,3) and is perpendicular to 2y=x−1. Leave your answer in the form y=mx +c
+36916 2y = x-1 y = 1/2 x - 1/2 slope , m = 1/2 perpindicular slope = - 1/m = -2
y = -2x + b sub in the point given to find 'b'
3 = -2(-1) + b b = 1
y = -2x+1
