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Find the equation of the line that passes through (-1,3) and is perpendicular to 2y=x−1. Leave your answer in the form y=mx +c 

 Jul 12, 2020
 #1
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2y = x-1         y = 1/2 x - 1/2      slope , m   = 1/2     perpindicular slope = - 1/m  = -2

 

y = -2x + b    sub in the point given to find 'b'

3 = -2(-1) + b      b = 1

 

y = -2x+1

 Jul 12, 2020

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