what is an equation of the line that is perpendicular to y-4 = 2(x-6) and passes through the point (-3, -5)
+781 y-4=2(x-6)
y-4=2x-12
y=2x-8
The slope of the line perpendicular must be -1/2. We then have y=-1/2x+b. We plug in the given point (-3,-5) to solve for b.
y=-1/2x+b
-5=-1/2(-3)+b
-5=3/2+b
b=-13/2
So the equation is y=-1/2x-13/2.
