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what is an equation of the line that is perpendicular to y-4 = 2(x-6) and passes through the point (-3, -5)

 Jul 14, 2020
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y-4=2(x-6)

y-4=2x-12

y=2x-8

 

The slope of the line perpendicular must be -1/2. We then have y=-1/2x+b. We plug in the given point (-3,-5) to solve for b.

 

y=-1/2x+b

-5=-1/2(-3)+b

-5=3/2+b

b=-13/2

 

So the equation is y=-1/2x-13/2.

 Jul 15, 2020

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