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Solve for n if  \(\frac{2-n}{n+1} + \frac{2n-4}{2-n} = 1\)

 Apr 5, 2024
 #1
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(2 -n)(2-n) + (2n -4) (n + 1)  =  (n + 1) ( 2 - n)

 

n^2 -4n + 4  + 2n^2 - 2n -4  = -n^2 + n + 2

 

3n^2 - 6n  = -n^2 + n + 2

 

4n^2 -7n   - 2  = 0

 

(4n + 1) ( n - 2)  = 0

 

Set each factor to 0 and  solve

 

n = -1/4     and  n =  2  (reject this answer....it makes a denominayor =  0 )

 

cool cool cool

 Apr 6, 2024

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