(2 -n)(2-n) + (2n -4) (n + 1) = (n + 1) ( 2 - n)
n^2 -4n + 4 + 2n^2 - 2n -4 = -n^2 + n + 2
3n^2 - 6n = -n^2 + n + 2
4n^2 -7n - 2 = 0
(4n + 1) ( n - 2) = 0
Set each factor to 0 and solve
n = -1/4 and n = 2 (reject this answer....it makes a denominayor = 0 )
