+0  
 
0
1607
1
avatar

The stopping distance for an automobile is F(s) = 1.1s + 0.055s^2 ft, where s is the speed in miles per hour. Use the linear approximation to estimate the change in stopping distance per additional miles per hour when s = 35 and when s = 50.

 Jan 23, 2017
 #1
avatar+37095 
0

When s = 35   F(s) = 105.88

when s = 50    F(s)= 192.5

 

F(50) - F(35) = 86.62     this is the difference between  stopping distance between 50 and 35 mph

so the average linear approximation would be    86.62 ft/ (50-35)mph = 5.775 ft / mph   

  In other words   each 1 mph increase in speed  increases stopping distance by 5.775 ft   (linear APPROXIMATON)

 Jan 24, 2017

4 Online Users

avatar
avatar
avatar