linear equation

To answer this one you must isolate the variable terms on one side of the equation and the non-variable on the other side using inverse operations. Then find a common denominator, rewrite each fraction then simplify and solve.
4y/5 - 14/15 = y/3
-14/15 = y/3 - 4y/5
-14/15 = 5y/15 -12y/15
-14/15 = -7y/15
2 = y

4y/5 - 14/15 = y/3

Obtain the LCM of 5, 15, and 3. It is 15.

Eliminate the denominators using the LCM. Multiplying every variable and non-variable terms by 15, you obtain,

12y - 14 = 5y

Now collect the variables to the left, the non-variable to the right. Ensure the signs changed accordingly.

12y - 5y = 14

Or, 7y = 14

Dividing both sides by 7, you obtain, y = 2