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avatar+256 

How many terms of the sequence 

\(\sqrt{1},\sqrt{2},\sqrt{3},\sqrt{4},\ldots \)

are less than or equal to 20?

 

indecisionindecisioncheeky

 Oct 19, 2018
 #1
avatar+19811 
+2

20^2 = 400         SO  there are 400 terms less than or equal to 20

 Oct 19, 2018
 #2
avatar+2328 
+3

To solve this, we first have to find the biggest term in the sequence, this is obviously the square root of 400. Since we know that the sequence is increasing by 1 for each step, we can conclude that there are exactly 400 terms.

 Oct 19, 2018
 #3
avatar+256 
+1

Thanks! that makes sense but how do you reconize the type of problem so easiely? ugh I appulaud the smarts! angel

 Oct 19, 2018
 #4
avatar+104804 
+1

Easy....both EP  and CU  are genuises   !!!!

 

 

 

cool cool cool

CPhill  Oct 19, 2018
 #5
avatar+19811 
+2

Thanx for the compliment....!   ( but I am more like a slide rule or abacus cheeky )

ElectricPavlov  Oct 19, 2018

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