Linear Equations

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Tran has $10000 to invest. She invested part of it in a term deposit paying 4% per annum and the remainder in bonds paying 5% per annum. If the total interest after 1 year was $440

Guest Jan 25, 2015

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Best Answer

+130540

+5

Call the amount invested at 4% , x

And call the amount invested at 5%, 10000 - x

And using I = Prt, where t= 1, we have

(x).04 + (10000 - x)(.05) = 440 simplify

.04x + 500 - .05x = 440 subtract 500 from both sides and combine like terms on the left

-.01x = -60 divide both sides by -.01

x = $6000 and this is the amount invested at 4%

And the amont invested at 5% is just 10000 - x = 10000 - 6000 = $4000

CPhill Jan 26, 2015

1⁺⁰ Answers

+130540

+5

Best Answer

Call the amount invested at 4% , x

And call the amount invested at 5%, 10000 - x

And using I = Prt, where t= 1, we have

(x).04 + (10000 - x)(.05) = 440 simplify

.04x + 500 - .05x = 440 subtract 500 from both sides and combine like terms on the left

-.01x = -60 divide both sides by -.01

x = $6000 and this is the amount invested at 4%

And the amont invested at 5% is just 10000 - x = 10000 - 6000 = $4000

CPhill Jan 26, 2015

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