+0  
 
0
40
3
avatar

The points (5,r) and (3,-2) lie on a line with a slope of -2.  What is the value of r?

 Mar 29, 2021

Best Answer 

 #1
avatar+101 
+2

To calculate the slope, we need the Delta Y over the Delta X. 

 

 

So, the delta Y is: -2 - r 

 

And the Delta X is: 3 - 5

 

We are left with:

\(\begin{array}{l}\frac{-2-r}{3-5}\ =\ -2\\ \\ =\ \frac{-2-r}{-2}=-2\\ =-2-r\ =\ 4\\ -r\ =\ 4\ +2\\ r\ =\ -6\\ \\ \\ \end{array}\)

 

Therefore the value of r = -6. 

 

Heres the proof

(5, -6) --> (3, -2)

 

m = -2 - (-6)  ÷  (3 - 5)

    = 4 / -2 = -2.

 

Therefore r = -2

 

 

 

(Solved by a 12 y/o - Yep! )

 Mar 29, 2021
 #1
avatar+101 
+2
Best Answer

To calculate the slope, we need the Delta Y over the Delta X. 

 

 

So, the delta Y is: -2 - r 

 

And the Delta X is: 3 - 5

 

We are left with:

\(\begin{array}{l}\frac{-2-r}{3-5}\ =\ -2\\ \\ =\ \frac{-2-r}{-2}=-2\\ =-2-r\ =\ 4\\ -r\ =\ 4\ +2\\ r\ =\ -6\\ \\ \\ \end{array}\)

 

Therefore the value of r = -6. 

 

Heres the proof

(5, -6) --> (3, -2)

 

m = -2 - (-6)  ÷  (3 - 5)

    = 4 / -2 = -2.

 

Therefore r = -2

 

 

 

(Solved by a 12 y/o - Yep! )

MathyGoo13 Mar 29, 2021
 #2
avatar+117787 
0

Good job, MG!!!!!

 

 

cool cool cool

CPhill  Mar 29, 2021
 #3
avatar+101 
+1

Thanks!

MathyGoo13  Mar 29, 2021

17 Online Users

avatar
avatar
avatar
avatar