Points T and U lie on a circle centered at O, and point P is outside the circle such that \(\overline{PT}\) and \(\overline{PU}\) are tangent to the circle. If \(\angle TPO = 26^{\circ},\) then what is the measure of minor arc TU, in degrees?
angle(TPO) = angle(UPO = 26o ---> angle(TPU = 52o
If minor arc(TU) = x, then major arc(TU) = 360o - x
angle(TPU) = ½·[ major arc(TU) - minor arc(TU) ]
52o = ½·[ ( 360o - x ) - ( x )]
52o = ½·[ 360o - 2x ]
52o = 180o - x
x = 128o
+223 
