P and Q are the solutions to the quadratic equation x^2+4x+6=0
P^2+Q^2 are the solutions to the quadratic equation x^2+bx+c=0
Find B+C
+128475 Using Vieta's Theorem
P + Q = -4 (1)
PQ = 6 (2)
Square both sides of (1) and we have that
P^2 + 2PQ + Q^2 = 16 sub in (2) for PQ and we have
P^2 + 2(6) + Q^2 = 16
P^2 + Q^2 + 12 = 16
P^2 + Q^2 = 4
So b = -4
And
(P^2)(Q^2) = c
(PQ)^2 = c
(6)^2 = c
So
b = - 4 and c = 36
And b + c = 32
