We have a triangle ABC such that AB=AC=8 and BC=10. What is the length of the median AM? Answer in radical form.

I understand that it is isosceles, but I dont understand how to go from here.

Thank you in advance :D

Guest Apr 26, 2020

#1**+1 **

The median of an isosceles triangle is perpendicular to the opposite side and goes to the middle of the opposite side.

For this problem, call the midpoint of the side opposite angle(A) "M".

BM = 5 and AB = 8 and triangle ABM is a right triangle ---> AM^{2} + 5^{2} = 8^{2}

Can you take it from here?

geno3141 Apr 26, 2020