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# little question...

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We have a triangle ABC such that AB=AC=8 and BC=10. What is the length of the median AM? Answer in radical form.

I understand that it is isosceles, but I dont understand how to go from here.

Apr 26, 2020

#1
+21017
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The median of an isosceles triangle is perpendicular to the opposite side and goes to the middle of the opposite side.

For this problem, call the midpoint of the side opposite angle(A) "M".

BM = 5 and AB = 8 and triangle ABM is a right triangle   --->   AM2 + 52  =  82

Can you take it from here?

Apr 26, 2020
#2
+1

hmm... That is what I thought but, I am confused that the median of AM would be a radical? I thought that the answer was 4? Srry...

Wait... would the answer be $$\sqrt{39}$$

Guest Apr 26, 2020
#3
+21017
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I think that it is the sqrt(39) ...

Apr 26, 2020
#4
+1

THX

Guest Apr 26, 2020