Hi,
How would I solve x+ln(x+6) = 7?
Would I have to bring the x to the other side and then solve using e^x-7=x+6 ?
\(x+ln(x+6) = 7\\ ln(x+6) = 7-x\\ e^{ln(x+6)} = e^{7-x}\\ x+6 = \frac{e^{7}}{e^x}\\ \frac{1}{x+6} = \frac{e^x}{e^{7}}\\ e^{7}= e^x(x+6)\\\)
mmm That didn't help at all.