Find the equation of the parabola with coordinates of the vertex (0,0) and equation of the axis y=0 and passing through the point (3,6)

Sorry I got mixed up with the questions

Thank you

\(y^2=4ax\\ \text{sub in x=3, y=6}\\ 36=4a*3\\ a=3\\ so\\ y^2=12x\)