log(3)+log(4)

log(12)

$${log}_{10}\left({\mathtt{3}}\right){\mathtt{\,\small\textbf+\,}}{log}_{10}\left({\mathtt{4}}\right) = {\mathtt{1.079\: \!181\: \!246\: \!047\: \!624\: \!8}}$$

$${log}_{10}\left({\mathtt{12}}\right) = {\mathtt{1.079\: \!181\: \!246\: \!047\: \!624\: \!9}}$$