Log(36,10) + 2log(5,10) - log(9,10)

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Guest Sep 4, 2014

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Log(36,10) + 2log(5,10) - log(9,10)

$$\\log36+2log5-log9\\
=log36+log25-log9\\
=log(36*25/9)\\
=log(100)\\
=2$$

Melody Sep 6, 2014

Melody · Answer 1 · 2014-09-06T10:19:20

Log(36,10) + 2log(5,10) - log(9,10)

$$\\log36+2log5-log9\\
=log36+log25-log9\\
=log(36*25/9)\\
=log(100)\\
=2$$