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7*(2^(3x-5)) = 53

 Oct 16, 2016
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7*(2^(3x-5)) = 53 divide both sides by 7

2^(3x - 5) = 7 4/7 take the log of both sides

(3x - 5) log(2) = log 7 4/7

(3x - 5) =log 7 4/7 / log (2)

(3x - 5) = 2.9205655

3x = 2.9205655 + 5

3x = 7.9205655 divide both sides by 3

x = 2.6401885

 Oct 16, 2016

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