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Find a/b when 2log(a-b)=log a + log b. I've tried everything I can think of but I have no idea how to solve it. Please help thanks!

 Jul 11, 2020
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By properties of logs, 2log(a - b) = log a + log b

==> log(2(a - b)) = log(a + b)

==> 2a - 2b = a + b

==> a = 3b

==> a/b = 3

 Jul 11, 2020

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