log2(x+1)=-3

Question

0

1767

1

log2(x+1)=-3

Guest May 25, 2015

+33654

+10

Best Answer

$log_2{(x+1)}=-3\rightarrow x+1=2^{-3}\rightarrow x=\frac{1}{8}-1\rightarrow x=-\frac{7}{8}$

.

Alan May 25, 2015

Alan · Answer 1 · 2015-05-25T10:11:38

$log_2{(x+1)}=-3\rightarrow x+1=2^{-3}\rightarrow x=\frac{1}{8}-1\rightarrow x=-\frac{7}{8}$

.