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log2(x+1)=-3

Guest May 25, 2015

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$$log_2{(x+1)}=-3\rightarrow x+1=2^{-3}\rightarrow x=\frac{1}{8}-1\rightarrow x=-\frac{7}{8}$$

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Alan  May 25, 2015
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1+0 Answers

 #1
avatar+26329 
+10
Best Answer

$$log_2{(x+1)}=-3\rightarrow x+1=2^{-3}\rightarrow x=\frac{1}{8}-1\rightarrow x=-\frac{7}{8}$$

.

Alan  May 25, 2015

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