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Log2y=1/3(log2 27power)

 Aug 4, 2015

Best Answer 

 #1
avatar+23245 
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log2y  =  (1/3)log227

Since a multiplier goes into the log expression as an exponent:

log2y  =  log2271/3

An exponent of 1/3 represents a cube root, so 271/3 = 3  (the cube root fo 27 is 3).

log2y  =  log23

So:  y = 3.

 Aug 5, 2015
 #1
avatar+23245 
+5
Best Answer

log2y  =  (1/3)log227

Since a multiplier goes into the log expression as an exponent:

log2y  =  log2271/3

An exponent of 1/3 represents a cube root, so 271/3 = 3  (the cube root fo 27 is 3).

log2y  =  log23

So:  y = 3.

geno3141 Aug 5, 2015

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