log3(81^-.2 = log(0.4152436465385058, 3) how did you get this answer as 4/5
Log_3(81^-.2)
=-0.2log_3(81)
=-0.2log_3(3^4)
=-0.2×4log_3(3)
=-0.8×1
=-0.8
=-4/5
log3 81 ^(-.2) =
-.2 * log3 81 =
-1/5 * 4 =
-4 / 5
Haha Chris.
I answered first.
Hey.....don't get too cocky........
I know where you live !!!!!
