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log5(7x - 4) = log5(5x - 3) how do I solve this?
 Mar 4, 2014

Best Answer 

 #1
avatar+259 
+3
The domain of definition: 5x - 3 > 0 => x > 5/3. log5(7x - 4) = log5(5x - 3) <=> 7x - 4 = 5x - 3. The further steps are traditional.
 Mar 4, 2014
 #1
avatar+259 
+3
Best AnswerThe domain of definition: 5x - 3 > 0 => x > 5/3. log5(7x - 4) = log5(5x - 3) <=> 7x - 4 = 5x - 3. The further steps are traditional.
scrutinizer Mar 4, 2014
 #2
avatar+2353 
0
scrutinizer:

The domain of definition: 5x - 3 > 0 => x > 5/3. log5(7x - 4) = log5(5x - 3) <=> 7x - 4 = 5x - 3. The further steps are traditional.



I think you might haver made a small typo scruntinizer because 5x-3 > 0 => x > 3/5
 Mar 4, 2014

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