log5(7x - 4) = log5(5x - 3)

Question

0

1206

2

log5(7x - 4) = log5(5x - 3) how do I solve this?

Guest Mar 4, 2014

+259

+3

Best AnswerThe domain of definition: 5x - 3 > 0 => x > 5/3. log5(7x - 4) = log5(5x - 3) <=> 7x - 4 = 5x - 3. The further steps are traditional.

scrutinizer Mar 4, 2014

scrutinizer · Answer 1 · 2014-03-04T08:13:09

The domain of definition: 5x - 3 > 0 => x > 5/3. log5(7x - 4) = log5(5x - 3) <=> 7x - 4 = 5x - 3. The further steps are traditional.

reinout-g · Answer 2 · 2014-03-04T11:12:03

scrutinizer:
The domain of definition: 5x - 3 > 0 => x > 5/3. log5(7x - 4) = log5(5x - 3) <=> 7x - 4 = 5x - 3. The further steps are traditional.

I think you might haver made a small typo scruntinizer because 5x-3 > 0 => x > 3/5