+130466 log6(2x-5)+1=log6(7x+10) note that "1 " can be written as log6(6) .....so we have
log6(2x-5)+log6(6) =log6(7x+10) and we can write
log6(2x-5)(6) =log6(7x+10) and now, we can just solve for this
(2x - 5)(6) = (7x + 10) simplify
12x - 30 = 7x + 10 add 30 to both sides, subtract 7x from both sides
5x = 40 divide by 5 on each side
x = 8
+130466 log6(2x-5)+1=log6(7x+10) note that "1 " can be written as log6(6) .....so we have
log6(2x-5)+log6(6) =log6(7x+10) and we can write
log6(2x-5)(6) =log6(7x+10) and now, we can just solve for this
(2x - 5)(6) = (7x + 10) simplify
12x - 30 = 7x + 10 add 30 to both sides, subtract 7x from both sides
5x = 40 divide by 5 on each side
x = 8
