log9(x^2+6x)=log9 (16)
Since the bases are the same, we can solve for......
x^2 + 6x = 16 subtract 16 from both sides
x^2 + 6x - 16 = 0 factor
(x - 2)(x + 8) = 0 and settting each factor to 0 . we have that x = 2 or x = -8
Both of the solutions are good, since neither produce a negative log
log9(x^2+6x)=log9 (16)
Since the bases are the same, we can solve for......
x^2 + 6x = 16 subtract 16 from both sides
x^2 + 6x - 16 = 0 factor
(x - 2)(x + 8) = 0 and settting each factor to 0 . we have that x = 2 or x = -8
Both of the solutions are good, since neither produce a negative log