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log9(x^2+6x)=log9 16

 May 13, 2015

Best Answer 

 #1
avatar+130516 
+5

 

 

log9(x^2+6x)=log9 (16)

Since the bases are the same, we can solve for......

x^2 + 6x = 16      subtract 16 from both sides

x^2 + 6x - 16 = 0     factor

(x - 2)(x + 8) = 0        and settting each factor to 0 . we have that x = 2 or x = -8

Both of the solutions are good, since neither  produce a negative log

 

  

 May 13, 2015
 #1
avatar+130516 
+5
Best Answer

 

 

log9(x^2+6x)=log9 (16)

Since the bases are the same, we can solve for......

x^2 + 6x = 16      subtract 16 from both sides

x^2 + 6x - 16 = 0     factor

(x - 2)(x + 8) = 0        and settting each factor to 0 . we have that x = 2 or x = -8

Both of the solutions are good, since neither  produce a negative log

 

  

CPhill May 13, 2015

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