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# log...

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3^(2x) - 8(3^x)=0

32x -8(3x)=0

Nov 13, 2018

#1
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I assume you want to solve for x

$$3^{2x} - 8(3^x) = 0\\ (3^x)^2 - 8(3^x) = 0\\ u = 3^x \\ u^2 - 8u = 0\\ u(u-8) = 0\\ u=0,~8\\ 3^x \neq 0,~\forall x \in \mathbb{R}\\ 3^x = 8\\ x = \log_3(8) =\dfrac{\ln(8)}{\ln(3)} \approx 1.893$$

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Nov 13, 2018