A car depreciates at a rate of 13% each year for the first 5 years after it is driven off of the lot. A recent high school graduate is looking to buy a car that is worth $23150.

Using logarithms, algebraically determine the number of years it will take the car to worth less than $15000.

Thank you for helping:)

Guest Jun 1, 2021

#1**+1 **

value = 23150 * ( 1 - .013)^{n}

15000 = 23150(.87)^{n}

15000/23150 = .87^{n}

log ( 15000/23150) = n log (.87) I think you can take it from here, no ?

ElectricPavlov Jun 1, 2021