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How do you solve log by hand? Please explain really simple. Thanks!

Guest Feb 21, 2017
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The most important thing to understand is that log is a power (or an indice)

 

If you can remember this one it will help a lot.  You can substitute other values in and use it for other questions.

 

\(log_{10}100=2\\ because\\ 10^2=100\)

 

Other than that you just have the log laws to learn

 

\(log_bX+log_bY=log_b(XY)\\ log_bX-log_bY=log_b(\frac{X}{Y})\\ log(X^y)=ylog(X)\\ \text{And the change of base law:}\\ log_bX=\frac{log_aX}{log_ab} \)

Melody  Feb 21, 2017

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