how to solve log64 2, i want to know the scheme
Your question isn't very clear. You should state it very clearly, so we can help you.
Log 64 base 2 = \(log_2 64 = log_2 2^6=6log_2 2=6*1=6 \)
or
\(log_{64}2=log_{64}64^{1/6}=(1/6)log_{64}64=(1/6)*1=1/6\)
