If \(\frac{^5log2}{^5log3}=m\) , then \(2^{2m}+2^{m+2}=?\)


Thank you very much for helping me.

Guest Apr 20, 2018

Your notation is not correct.

What is the little 5 for?

Melody  Apr 21, 2018

The little 5 is derived from the question itself. I don't know if the question is wrong from the beginning or not. But that what the question is. I can post a picture of it if you want.

Note : i am not a native english speaker, i am very sorry for any mispell or miscommunication. I just need help :(

Guest Apr 21, 2018

Well the 5 does not make sense but lets look at a possible meaning.


Note that  when an English speaking person sees    \(log_25\)

They would SAY it as                                        log of 5 base 2     or   log 5 base 2


\(m=\frac{log_25}{log_35}\\ m=\frac{log5}{log2}\div \frac{log5}{log3}\\ m=\frac{log5}{log2}\times \frac{log3}{log5}\\ m=\frac{log3}{log2}\\ mlog2=log3\\ log2^m=log3\\ 2^m=3\\~\\ \)

\(2^{2m}+2^{m+2}\\ =(2^m)^2+2^m*2^2\\ =3^2+3*4\\ =9+12\\ =21 \)



If the pic looks a little different perhaps you should post that  laugh

Melody  Apr 23, 2018

Thank you very much for solving it! And yes, after i did some googling, turns out there is a difference between how the english use of notation and our county use of log notation.

Guest Apr 23, 2018

15 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.