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If \(\frac{^5log2}{^5log3}=m\) , then \(2^{2m}+2^{m+2}=?\)

 

Thank you very much for helping me.

 Apr 20, 2018
 #1
avatar+99214 
+1

Your notation is not correct.

What is the little 5 for?

 Apr 21, 2018
 #2
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+1

The little 5 is derived from the question itself. I don't know if the question is wrong from the beginning or not. But that what the question is. I can post a picture of it if you want.

Note : i am not a native english speaker, i am very sorry for any mispell or miscommunication. I just need help :(

Guest Apr 21, 2018
 #3
avatar+99214 
+2

Well the 5 does not make sense but lets look at a possible meaning.

 

Note that  when an English speaking person sees    \(log_25\)

They would SAY it as                                        log of 5 base 2     or   log 5 base 2

 

\(m=\frac{log_25}{log_35}\\ m=\frac{log5}{log2}\div \frac{log5}{log3}\\ m=\frac{log5}{log2}\times \frac{log3}{log5}\\ m=\frac{log3}{log2}\\ mlog2=log3\\ log2^m=log3\\ 2^m=3\\~\\ \)

\(2^{2m}+2^{m+2}\\ =(2^m)^2+2^m*2^2\\ =3^2+3*4\\ =9+12\\ =21 \)

 

 

If the pic looks a little different perhaps you should post that  laugh

 Apr 23, 2018
 #4
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+1

Thank you very much for solving it! And yes, after i did some googling, turns out there is a difference between how the english use of notation and our county use of log notation.

Guest Apr 23, 2018

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