For what x will $7-\log_{36}{x}+\frac{13}{2}=13$ ?
Isolate the log on one side to get \(\log_{36}{x} = -\frac{1}{2}.\)
From there, we get \(x^{-\frac{1}{2}} = 36.\)
Hope this helps.
log36 = 7-13 + 13/2
LOG36 x = 1/2
36log36x = 361/2
x = 6
+1224 
