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For what x  will $7-\log_{36}{x}+\frac{13}{2}=13$ ?

 Feb 22, 2021
 #1
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Isolate the log on one side to get \(\log_{36}{x} = -\frac{1}{2}.\)

 

From there, we get \(x^{-\frac{1}{2}} = 36.\)

 

Hope this helps.

 Feb 22, 2021
 #2
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log36  = 7-13 + 13/2

 

LOG36 x    = 1/2

 

36log36x = 361/2

x = 6

 Feb 22, 2021

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