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log(a)(2x^2-7)=2log(a)(x-1)

 Jul 4, 2016
 #1
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loga(2x^2-7) = 2loga(x-1)

 

loga(2x^2-7) = loga(x-1)^2

 

2x^2 - 7 = (x - 1)^2

 

2x^2 - 7 = x^2 - 2x + 1

 

x^2 + 2x - 8 = 0

 

(x + 4)(x - 2)  = 0

 

Can you take it from here?

 Jul 4, 2016

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