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If loga(s) = 5 and loga(t) = 10, then loga(s/t2) = ?

 Jun 27, 2018
 #1
avatar+130466 
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loga s  = 5    loga t   =10

 

In exponential form, we have

 

a^5  = s       and  a^10  =  t

 

So

 

loga (s / t^2 )  =

 

loga [a^5 / (a^10)^2 ]  =

 

loga [ a^5 / a^20 ]  =

 

loga  a^(-15)        and by a log property we can write

 

-15 * loga a  =

 

 ( Note  loga a   =  1  )

 

-15 * 1  =

 

-15

 

cool cool cool

 Jun 27, 2018
edited by CPhill  Jun 27, 2018
 #2
avatar+26396 
0

If loga(s) = 5 and loga(t) = 10, then loga(s/t2) = ?

 

loga(s)=5loga(t)=10loga(s)2loga(t)=5210loga(s)2loga(t)=15loga(s)loga(t2)=15loga(st2)=15

 

laugh

 Jun 28, 2018

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