If loga(s) = 5 and loga(t) = 10, then loga(s/t2) = ?
loga s = 5 loga t =10
In exponential form, we have
a^5 = s and a^10 = t
So
loga (s / t^2 ) =
loga [a^5 / (a^10)^2 ] =
loga [ a^5 / a^20 ] =
loga a^(-15) and by a log property we can write
-15 * loga a =
( Note loga a = 1 )
-15 * 1 =
-15
loga(s)=5loga(t)=10loga(s)−2⋅loga(t)=5−2⋅10loga(s)−2⋅loga(t)=−15loga(s)−loga(t2)=−15loga(st2)=−15