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logx143=0.96

 

Graph this on a graphing calculator and find the value of x where y drops below 30.

 Dec 13, 2016
edited by rarinstraw1195  Dec 14, 2016
 #1
avatar+118703 
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You cannot graph it as it because there is no y

 

 

logx143=0.96

 

logx143=0.96log143logx=0.96logx=log(143)/0.9610logx=10log(143)/0.96x=10log(143)/0.96

10^(log(143)/0.96) = 175.84972994163184

 

x175.84972994163184

 

check

 

log(143,175.84972994163184) = 0.9599999999999999

 

you are not goint to get any closer than that :)

 Dec 14, 2016
 #3
avatar+5265 
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*facepalm* my bad, forgot there's no y. Thanks Melody :)

rarinstraw1195  Dec 14, 2016
 #2
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logx143=0.96

 

x^.96 = 143

x = 143^(1/0.96)

x =175.85, because

175.85^0.96 = 143

 Dec 14, 2016

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