logx143=0.96
Graph this on a graphing calculator and find the value of x where y drops below 30.
You cannot graph it as it because there is no y
logx143=0.96
logx143=0.96log143logx=0.96logx=log(143)/0.9610logx=10log(143)/0.96x=10log(143)/0.96
10^(log(143)/0.96) = 175.84972994163184
x≈175.84972994163184
check
log(143,175.84972994163184) = 0.9599999999999999
you are not goint to get any closer than that :)