logx143=0.96
Graph this on a graphing calculator and find the value of x where y drops below 30.
You cannot graph it as it because there is no y
logx143=0.96
\(log_x143=0.96\\ \frac{log143}{logx}=0.96\\ logx=log(143)/0.96\\ 10^{logx}=10^{log(143)/0.96}\\ x=10^{log(143)/0.96}\\\)
10^(log(143)/0.96) = 175.84972994163184
\(x\approx 175.84972994163184\)
check
log(143,175.84972994163184) = 0.9599999999999999
you are not goint to get any closer than that :)