+0

Logarithms

+1
279
3
+5210

logx143=0.96

Graph this on a graphing calculator and find the value of x where y drops below 30.

rarinstraw1195  Dec 13, 2016
edited by rarinstraw1195  Dec 14, 2016
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#1
+91780
0

You cannot graph it as it because there is no y

logx143=0.96

$$log_x143=0.96\\ \frac{log143}{logx}=0.96\\ logx=log(143)/0.96\\ 10^{logx}=10^{log(143)/0.96}\\ x=10^{log(143)/0.96}\\$$

10^(log(143)/0.96) = 175.84972994163184

$$x\approx 175.84972994163184$$

check

log(143,175.84972994163184) = 0.9599999999999999

you are not goint to get any closer than that :)

Melody  Dec 14, 2016
#3
+5210
0

*facepalm* my bad, forgot there's no y. Thanks Melody :)

rarinstraw1195  Dec 14, 2016
#2
0

logx143=0.96

x^.96 = 143

x = 143^(1/0.96)

x =175.85, because

175.85^0.96 = 143

Guest Dec 14, 2016

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