#1**+3 **

x=6

Log3 ((x+3)(x-5) ) = 2

log3 (x^2-2x-15) = 2

x^2 - 2x - 15 = 3^2

x^2 -2x-24 =0

(x-6)(x+4) = 0 x = 6 or -4 (throw out....cannot have log of a negative )

ElectricPavlov May 9, 2021

#2**+1 **

Oh it makes sense now! I only had issues when it came to the part when there was the 3^2, so I must've forgotten a log rule there.

stressedmathkid123
May 9, 2021