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 LOGARITHMS

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Oh man. I've seen my fair share of tough math but nothing like logs! We just started this unit and a failed my test. Though, were taking a retake tommrow but it won'y help me if I'm not ready. Looked everywhere for help then remembered this site, heh I know, the only time I can remember to visit this site is when I need help, yeah, I get it. Anyways, straight to the point. I just need a few pointers an example really. The simplest one looks like 16^x=2^3. If anyone can help I'd be greatful.

 Mar 3, 2016

Best Answer 

 #1
avatar+5265 
+4

16^x=2^3 = x=(ln(8)/ln(16))

 Mar 3, 2016

4+0 Answers

 #1
avatar+5265 
+4
Best Answer

16^x=2^3 = x=(ln(8)/ln(16))

rarinstraw1195 Mar 3, 2016
 #2
avatar+5265 
-1

Or 0.75

rarinstraw1195  Mar 3, 2016
 #3
avatar+129899 
+4

16^x  = 2^3    let's get the bases the same, zegroes

 

[2^4]^x  = 2^3

 

2^(4x) = 2^3   since the bases are the same, solve for the exponents

 

4x = 3      divide by 4 on both sides

 

x = 3/4

 

 

cool cool cool

 Mar 3, 2016
 #4
avatar+3502 
0

Thanks guys. Still a little hard to grasp but I gues I get it.

 Mar 4, 2016

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