logx(6) = 15

http://www.sosmath.com/algebra/logs/log4/log47/log47.html try this website it should help;)

-Ally

sorry it doesn't answer my question.

log_x(6) = 15

logx(6) = 15

It is very easy. To find x, you use:

x^6=15 take the 6th root of both sides:

x=15^1/6=1.570......etc, so that:

1.570^6=15 Approx. because of rounding off 1.5704178.......etc.