+0  
 
0
798
2
avatar+4 

Bonjour,

 

Supposons que notre variable aléatoire X suit une loi normale centrée réduite.

 

0,6217 = P(X<0,xx (deux chiffres significatifs))

0,yyy=P(-2,96<X<0,25) (trois chiffres significatifs).

merci

 Mar 6, 2016

Best Answer 

 #2
avatar+26393 
+10

Standard normal distribution

 

P ( x < 0,31 ) = 0.62172

 

P(-2.96 < x < 0.25 ) = 0.59871 - ( 1 - 0.99846 ) = 0.59871 - 0.00154 = 0.59717 = 0.597(17)

 

 

 

laugh

 

 

 

 

 Mar 6, 2016
 #1
avatar+8262 
+5

French translation:

 

Hello,   Suppose our random variable X has a standard normal distribution .   0.6217 = P ( X <0 , xx ( two significant figures) ) 0 , yyy = P ( -2.96 <X < 0.25) ( three significant figures) .

Thank you

 Mar 6, 2016
 #2
avatar+26393 
+10
Best Answer

Standard normal distribution

 

P ( x < 0,31 ) = 0.62172

 

P(-2.96 < x < 0.25 ) = 0.59871 - ( 1 - 0.99846 ) = 0.59871 - 0.00154 = 0.59717 = 0.597(17)

 

 

 

laugh

 

 

 

 

heureka Mar 6, 2016

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