+0  
 
0
416
2
avatar+266 

can u explain 

 Feb 8, 2016
 #1
avatar+111321 
0

1.   x^4 -52x + 576  = 0

 

This has no real solutions.........see the graph, here :https://www.desmos.com/calculator/dniadv9jnx

 

 

2.   x^3  = 216

 

x^3  - 216  = 0       factor  as a difference of cubes

 

(x -6) (x^2 + 6x + 36)  = 0       

 

Setting each factor to 0, it's clear that x = 6  is the real solution

 

Setting x^2 + 6x + 36  to 0    and using the quadratic formula we obtain  two non-real solutions :

 

-3-3 i sqrt(3)   and  -3+3 i sqrt(3)   [the last answer ]

 

 

 

cool cool cool

 Feb 8, 2016
 #2
avatar+266 
0

thank you so much CPhill!

 Feb 8, 2016

8 Online Users

avatar