​ lol pls help

1.   x^4 -52x + 576  = 0

This has no real solutions.........see the graph, here :https://www.desmos.com/calculator/dniadv9jnx

2.   x^3  = 216

x^3  - 216  = 0       factor  as a difference of cubes

(x -6) (x^2 + 6x + 36)  = 0       

Setting each factor to 0, it's clear that x = 6  is the real solution

Setting x^2 + 6x + 36  to 0    and using the quadratic formula we obtain  two non-real solutions :

-3-3 i sqrt(3)   and  -3+3 i sqrt(3)   [the last answer ]

thank you so much CPhill!