An airplane of mass 1.63E+4 kg is moving at 64.5 m/s. The pilot then revs up the engine so that the forward thrust of the propeller becomes 7.87E+4 N. If the force of air resistance has a magnitude of 3.08E+4 N, find the speed of the airplane after it has traveled 590 m. Assume that the airplane is in level flight throughout this motion.
+33616 Net force, F = (7.87 - 3.08)*104 N = 4.79*104 N
Acceleration, a = F/mass so a = 4.79*104/1.63*104 m/s2 ≈ 2.93865 m/s2
Use v2 = u2 + 2*a*s where v = final velocity, u = initial velocity and s = distance travelled to get the final velocity.
i.e. v = sqrt(64.52 + 2*2.93865*590) m/s
