If in a division successive substrahends are 690, 2415 and 2070, and the remainder is 1, find the dividend, the devisor, and the quotient. Thanks.
The sum of the substrahends and the remainder is equal to the dividend. Hence, the dividend is:690 + 2,415 + 2,070 + 1 =95,221. Since the GCD or GCF of 690, 2,415 and 2,070 is 345, then 345 is the devisor. And the quotient would be:95,221 / 345 = 276 with a remainder of 1.
I think the questioner meant "subtrahend" not "substrahend", but the meaning is clear.
Sorry CPhill: I screwed up my "invisible zeros"!!!. I assumed that since 690 is the first subtrahend out of three, I automatically added two zeros in my calculator!!. Thus, 690 should actually be 69000!. Similarly, the second subtrahend of 2,415 should be 24150!. And the third and last should remain 2070 plus the remainder of 1. So that the whole dividend should be:[690 x100] + [2,415 x 10] + 2,070 + 1 =95,221!!!.
