((m^2)(n^2)-(m^3)n)/(mn)

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Guest Nov 20, 2014

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Best Answer

(m^2)(n^2)-(m^3)n)/(mn) the greatest common factor in the numerator is m^2n...so we have

[m^2n] [ n - m] / [mn] =

m [ n - m ] =

mn - m^2

CPhill Nov 20, 2014

CPhill · Answer 1 · 2014-11-20T05:39:57

(m^2)(n^2)-(m^3)n)/(mn) the greatest common factor in the numerator is m^2n...so we have

[m^2n] [ n - m] / [mn] =

m [ n - m ] =

mn - m^2