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(m+3)^2=m^2+3^2=m^2+9 

 

could anyone tell me if the working out is correct & why?

 Apr 11, 2016
 #1
avatar+56 
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That is totally incorrect, sorry.

 

\((m+3)(m+3)= {m}^{2}+6m+9\)

 Apr 11, 2016
 #2
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No because you need to foil

First

Inner 

Outer

Last

 

(m+3)^2

 

(m+3)*(m+3)

 

m2+3m+3m+32

 

m2+6m+9

 Apr 11, 2016
 #3
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0

haha thanks, i didnt expect it to be correct

 Apr 11, 2016
 #4
avatar+56 
0

You can always test the equation by simply making m, a number

 

if m=1 , (1+3)^2 =(?) (1)^2+3^2

 Apr 11, 2016

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