N = A + 125
J = A/2
N + J + A = (A+125) + A/2 + A = 765
Find the number of N, J and A
N = A + 125
J = A/2
N + J + A = (A+125) + A/2 + A = 765
a+125 + a/2 + a = 765
2.5 a = 765 - 125
a = 256 n = 256 + 125 =381 j = 256/2 = 128
N = A + 125
J = A/2
N + J + A = (A+125) + A/2 + A = 765
a+125 + a/2 + a = 765
2.5 a = 765 - 125
a = 256 n = 256 + 125 =381 j = 256/2 = 128