+0  
 
0
46
1
avatar

N = A + 125

J = A/2

N + J + A = (A+125) + A/2 + A = 765

Find the number of N, J and A

 Apr 13, 2021

Best Answer 

 #1
avatar+31581 
+1

N = A + 125

J = A/2

N + J + A = (A+125) + A/2 + A = 765   

 

                 a+125    + a/2   + a    = 765

 

                  2.5 a = 765 - 125

                       a = 256          n = 256 + 125 =381            j = 256/2   = 128
 

 Apr 13, 2021
edited by ElectricPavlov  Apr 13, 2021
 #1
avatar+31581 
+1
Best Answer

N = A + 125

J = A/2

N + J + A = (A+125) + A/2 + A = 765   

 

                 a+125    + a/2   + a    = 765

 

                  2.5 a = 765 - 125

                       a = 256          n = 256 + 125 =381            j = 256/2   = 128
 

ElectricPavlov Apr 13, 2021
edited by ElectricPavlov  Apr 13, 2021

76 Online Users

avatar
avatar
avatar
avatar
avatar
avatar
avatar