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M is the midpoint of AB. The cordinates of A Are (-2,3) and the cordinates of M are (1,0). Find the cordinates of B

 Jul 16, 2015

Best Answer 

 #1
avatar+26367 
+13

M is the midpoint of AB. The cordinates of A Are (-2,3) and the cordinates of M are (1,0). Find the cordinates of B

 

$$\small{\text{$
\begin{array}{rcl}
\vec{M}&=&\dfrac{1}{2}(\vec{A}+\vec{B})\\\\
2\cdot \vec{M}&=&\vec{A}+\vec{B}\\\\
2\cdot \vec{M}-\vec{A}&=&\vec{B}\\\\
\vec{\mathbf{B}}& \mathbf{=} &\mathbf{ 2\cdot} \vec{\mathbf{M}} \mathbf{ -} \vec{\mathbf{A}} \\\\
\vec{B} &=& 2\cdot \binom10 - \binom{-2}{3}\\\\
\vec{B} &=& \binom20 - \binom{-2}{3}\\\\
\vec{B} &=& \binom{2+2}{0-3}\\\\
\vec{\mathbf{B}} &\mathbf{=}& \mathbf{\binom{4}{-3}}\\\\
\end{array}
$}}$$

 

 B  is (4,-3)

 

 Jul 16, 2015
 #1
avatar+26367 
+13
Best Answer

M is the midpoint of AB. The cordinates of A Are (-2,3) and the cordinates of M are (1,0). Find the cordinates of B

 

$$\small{\text{$
\begin{array}{rcl}
\vec{M}&=&\dfrac{1}{2}(\vec{A}+\vec{B})\\\\
2\cdot \vec{M}&=&\vec{A}+\vec{B}\\\\
2\cdot \vec{M}-\vec{A}&=&\vec{B}\\\\
\vec{\mathbf{B}}& \mathbf{=} &\mathbf{ 2\cdot} \vec{\mathbf{M}} \mathbf{ -} \vec{\mathbf{A}} \\\\
\vec{B} &=& 2\cdot \binom10 - \binom{-2}{3}\\\\
\vec{B} &=& \binom20 - \binom{-2}{3}\\\\
\vec{B} &=& \binom{2+2}{0-3}\\\\
\vec{\mathbf{B}} &\mathbf{=}& \mathbf{\binom{4}{-3}}\\\\
\end{array}
$}}$$

 

 B  is (4,-3)

 

heureka Jul 16, 2015

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