+0  
 
0
687
1
avatar

magniyude of the vector given a horizontal component of 10 and a vertical component of 10

 Nov 17, 2014

Best Answer 

 #1
avatar+33661 
+5

√(102 + 102) = 10√2

$${\mathtt{10}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{2}}}} = {\mathtt{14.142\: \!135\: \!623\: \!730\: \!950\: \!5}}$$

.

 Nov 17, 2014
 #1
avatar+33661 
+5
Best Answer

√(102 + 102) = 10√2

$${\mathtt{10}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{2}}}} = {\mathtt{14.142\: \!135\: \!623\: \!730\: \!950\: \!5}}$$

.

Alan Nov 17, 2014

0 Online Users