make x the subject of the formular

 next,if x:y:z=2:5:3 , find the value(s) of x satisfyinh the formular in (a)

$$\\y=\frac{x}{2}*5=\frac{5x}{2}, \qquad z=\frac{x}{2}*3=\frac{3x}{2}\\\\\\ x=\frac{10z-2y}{5z}\\\\ x=\frac{10*\frac{3x}{2}-2*\frac{5x}{2}}{5*\frac{3x}{2}}\\\\ x=\frac{15x-5x}{\frac{15x}{2}}\\\\ x=10x*\frac{2}{15x}\qquad \mbox{Note x cannot equal 0}\\\\ x=\frac{4}{3}$$

I think that your part a question can be simplified further to

$$x=\dfrac{10z-2y}{5z}$$

I found the answer in (a) is  $${\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{y}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{zy}}\right)}{{\mathtt{\,-\,}}\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{zy}}\right)}}$$  , how to solve (b)?

$$x=\dfrac{10zy-2y^2}{5zy} = 2-\dfrac{2}{5}*\dfrac{y}{z} \quad | \quad \dfrac{y}{z} = \dfrac{5}{3}\\\\ x= 2 - \frac{2}{3} = 1\frac{1}{3}$$

You beat me by a hair heureka     

Hi,  Melody

excuse please

1/z + x/y = 5/y - 3x / 2y     rearrange

3x / 2y  + x / y  = 5/y - 1/z    simplify

5x / 2y  = [5z - y ] / yz

5x = 2[5z - y ] / z

x  = (2/5) [ 5z - y ] / z = [ 10z - 2y ] /  [5z] = 2 - 2y/5z = 2 -  (2/5) (y/z)....but (y/z)  = 5/3..so we have

x =2 - (2/5)(5/3)  =  2 - 2/3  = 6/3 - 2/3 = 4/3

There is nothing to excuse Heureka, you beat me fair and square.  LOL