Hi good people!,
kindly just check if I did this correctly?
Make r the subject:
\(F=K{Q1Q2 \over r^2}\)
I did this:
devide by K:
\({F \over K}={Q1Q2 \over \ r^2}\)
Multiply by r^2
\({Fr^2 \over K}=Q1Q2\)
Multiply by K
\(Fr^2=K(Q1Q2)\)
Devide by F
\(r^2={K(Q1Q2) \over F}\)
\(r= \sqrt{K({Q1Q2} \over F}\)
Thanx for the time!
+9466 Your method is correct, but you can do it without dividing by K and then multiplying by K :
\(F\,=\,K\cdot\frac{Q_1Q_2}{r^2} \\~\\ F\,=\,\frac{K(Q_1Q_2)}{r^2}\)
Multiply both sides of the equation by r2
\(Fr^2\,=\,K(Q_1Q_2)\)
Divide both sides of the equation by F .
\(r^2\,=\,\frac{K(Q_1Q_2)}{F} \)
If we need to include both solutions for r , then we need to take the positive and negative square root of both sides.
\(r\,=\,\pm\sqrt{\frac{K(Q_1Q_2)}{F}}\)
+9466 Your method is correct, but you can do it without dividing by K and then multiplying by K :
\(F\,=\,K\cdot\frac{Q_1Q_2}{r^2} \\~\\ F\,=\,\frac{K(Q_1Q_2)}{r^2}\)
Multiply both sides of the equation by r2
\(Fr^2\,=\,K(Q_1Q_2)\)
Divide both sides of the equation by F .
\(r^2\,=\,\frac{K(Q_1Q_2)}{F} \)
If we need to include both solutions for r , then we need to take the positive and negative square root of both sides.
\(r\,=\,\pm\sqrt{\frac{K(Q_1Q_2)}{F}}\)
