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Marbles in Bags

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Bag A has 3 white and 2 black marbles. Bag B has white 4 and black 3 marbles.

Suppose we draw a marble at random from Bag A and put it in Bag B. After doing this, we draw a marble at random from Bag B, which turns out to be white. Given this information, what is the probability that the marble we moved from Bag A to Bag B is white?

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I got an answer of 103/245, but it was wrong. How do i approach this problem, and if possible, please provide multiple hints, and paybe the solution! Thanks!

Sep 16, 2018
edited by Max0815  Sep 16, 2018

#1
+6187
+2

A = 3W2B

B = 4W3B

transfer W from A to B gives: A = 2W2B, B = 5W3B, Probability 3/5

transfer B from A to B gives : A = 3W1B, B = 4W4B, Probability 2/5

Let event X be the event that the moved marble was white

Let event Y be the event that the marble chosen from bag B was white

We want P[X | Y]

$$P[X | Y] = \dfrac{P[Y|X]P[X]}{P[Y]}$$

$$P[Y|X] = \dfrac 5 8\\ \\ P[X] = \dfrac 3 5 \\ \\ P[Y] = \dfrac 5 8 \dfrac 3 5 + \dfrac 4 8 \dfrac 2 5 = \dfrac{23}{40}$$

$$P[X|Y] = \dfrac{\frac 5 8 \cdot \frac 3 5}{\frac{23}{40}} = \dfrac{15}{23}$$

Sep 16, 2018
edited by Rom  Sep 16, 2018
edited by Rom  Sep 16, 2018
#2
+194
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Thank you very much!!!!!!!

Sep 16, 2018