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A box contains 2 red marbles, 3 green marbles, and 3 blue marbles.

If we choose a marble, then another marble without putting the first one back in the box, what is the probability that the first marble will be green and the second will be blue?

Guest Nov 27, 2018
edited by Guest  Nov 27, 2018

Best Answer 

 #1
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The probability for the first marble to be green:  3/2+3+3 = 3/8

The probability for the first marble to be blue: 3/2+2+3 = 3/7

 

Answer: 3/8*3/7= 9/56blush

otaku  Nov 27, 2018
 #1
avatar+22 
+2
Best Answer

The probability for the first marble to be green:  3/2+3+3 = 3/8

The probability for the first marble to be blue: 3/2+2+3 = 3/7

 

Answer: 3/8*3/7= 9/56blush

otaku  Nov 27, 2018

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