A box contains 2 red marbles, 3 green marbles, and 3 blue marbles.
If we choose a marble, then another marble without putting the first one back in the box, what is the probability that the first marble will be green and the second will be blue?
The probability for the first marble to be green: 3/2+3+3 = 3/8
The probability for the first marble to be blue: 3/2+2+3 = 3/7
Answer: 3/8*3/7= 9/56
