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f(x)=x^4-9x^3+12x^2+80x-192
 Feb 18, 2014
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f(x)=x^4-9x^3+12x^2+80x-192



Where is the question? Do you want me to factorise it?
The answer to that is

f(x) = (x-4) 3(x+3)

so the roots of the graph will be, a triple root at x=4 and another root at x=-3

NOW if you want me to explain any of the this you will need to be more specific.
 Feb 19, 2014

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